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Continue rapport
+18
-4
+18
-4
rapport/context.typ
+18
-4
rapport/context.typ
···
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La complexité de l'expression, et la présence d'un $min$ au lieu de simplement un $op("clip")$ est dûe au fait que l'avantage $A_(cal(P)', R) (s, a)$ peut être négatif:
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+
#let named_point = (x, y, shape: "@", color: black, side: right, content) => edge((x, y), shape + "-", (x+0.01, y), label-side: side, stroke: color, text(fill: color, content))
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/ Si l'avantage est positif: #fletcher.diagram(
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spacing: (2.7em, 2em),
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-
edge((-5, 0), "->", (5, 0)),
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edge((-5, 0.25), "-", (-5, -0.25), label-side: left)[$0$]
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node((-5, 0))[$0$],
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edge((-5, 0), "|->", (5, 0), stroke: luma(150)),
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edge((-1, 0), "|-|", (1, 0), extrude: (1, -1, 0) ),
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named_point(-1, 0, shape: "|")[$1-epsilon$],
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named_point(1, 0, shape: "|")[$1+epsilon$],
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named_point(0, 0)[$cal(P)$],
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named_point(-4, 0, color: red, side: left)[$cal(P)'$],
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named_point(0.5, 0, color: green, side: left)[$cal(P)'$],
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)
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$
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L(s, a, cal(P), cal(P)', R) = min(
···
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$
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/ Si l'avantage est négatif: #fletcher.diagram(
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spacing: (2.7em, 2em),
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edge((-5, 0), "->", (5, 0)),
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edge((-5, 0.25), "-", (-5, -0.25), label-side: left)[$0$]
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node((5, 0))[$0$],
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edge((-5, 0), "<-|", (5, 0), stroke: luma(150)),
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edge((-2, 0), "|-|", (2, 0), extrude: (1, -1, 0) ),
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named_point(-2, 0, shape: "|")[$1-epsilon$],
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named_point(2, 0, shape: "|")[$1+epsilon$],
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named_point(0, 0)[$cal(P)$],
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named_point(-4, 0, color: red, side: left)[$cal(P)'$],
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named_point(1, 0, color: green, side: left)[$cal(P)'$],
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)
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$
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L(s, a, cal(P), cal(P)', R) = max(