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cmd/cue: add a test for `cue mod publish` on a non-tidy module
This succeeds right now, but it shouldn't, and we already have
a TODO in modpublish.go for this reason.
This is important not only by itself as a default sanity check,
but also for the upcoming change to consistently suggest
that the user run 'cue mod fix' when an operation on the current module
fails because it lacks a language.version field.
Signed-off-by: Daniel Martí <mvdan@mvdan.cc>
Change-Id: I8e0c91c3a526dbe2753e1e51d504146b2d85f1a8
Reviewed-on: https://review.gerrithub.io/c/cue-lang/cue/+/1195727
Reviewed-by: Paul Jolly <paul@myitcv.io>
Unity-Result: CUE porcuepine <cue.porcuepine@gmail.com>
TryBot-Result: CUEcueckoo <cueckoo@cuelang.org>
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cmd/cue/cmd/testdata/script/modpublish_non_tidy.txtar
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cmd/cue/cmd/testdata/script/modpublish_non_tidy.txtar
···
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# Test that cue mod publish fails when the module is not tidy
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# because one of the required dependencies is missing from module.cue.
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env OLD_CUE_REGISTRY=${CUE_REGISTRY}
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memregistry MEMREGISTRY
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env CUE_REGISTRY=$MEMREGISTRY+insecure
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# TODO(mvdan): mod publish does not check tidiness right now.
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exec cue mod publish v1.0.0
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# Sanity check that we can tidy the module and then publish again.
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# Note that the dependency is in the original registry populated from _registry/.
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env CUE_REGISTRY=${OLD_CUE_REGISTRY}
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exec cue mod tidy
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env CUE_REGISTRY=$MEMREGISTRY+insecure
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cmp cue.mod/module.cue cue.mod/module.cue.tidy
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exec cue mod publish v1.0.1
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-- cue.mod/module.cue --
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module: "main.org@v1"
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language: version: "v0.9.0"
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source: kind: "self"
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-- cue.mod/module.cue.tidy --
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module: "main.org@v1"
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language: {
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version: "v0.9.0"
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}
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source: {
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kind: "self"
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}
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deps: {
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"example.com@v0": {
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v: "v0.0.1"
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}
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}
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-- main.cue --
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package main
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import "example.com@v0:main"
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main
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-- _registry/example.com_v0.0.1/cue.mod/module.cue --
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module: "example.com@v0"
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language: version: "v0.8.0"
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-- _registry/example.com_v0.0.1/top.cue --
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package main
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"example.com@v0": "v0.0.1"