this repo has no description
fix: improve error message when inferring output name
+12
-3
+12
-3
src/main.rs
+12
-3
src/main.rs
···
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input: &Option<String>,
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extract: bool,
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) -> Result<String, io::Error> {
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let filename = match get_input_filename(input) {
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Ok(name) => name,
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Err(_) => {
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return Err(io::Error::new(
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io::ErrorKind::Other,
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"error: can't infer output name while using stdin for input",
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))
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}
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};
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match extract {
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true => Ok(compressor.default_extracted_filename(Path::new(get_input_filename(input)?))),
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-
false => Ok(compressor.default_compressed_filename(Path::new(get_input_filename(input)?))),
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true => Ok(compressor.default_extracted_filename(Path::new(filename))),
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false => Ok(compressor.default_compressed_filename(Path::new(filename))),
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}
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}
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···
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false => CmprssOutput::Pipe(std::io::stdout()),
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true => {
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if args.output.is_none() {
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-
if !std::io::stdin().is_terminal() {
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if !std::io::stdin().is_terminal() && args.input.is_some() {
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// Stdin is being used as the input, so use the 'input' file as the output
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CmprssOutput::Path(Path::new(get_input_filename(&args.input)?))
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} else {