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drm/amd/display: fix math_mod() using arg1 instead of arg2

[Why]
math_mod() multiplied by arg1 instead of arg2, returning a wrong
result for any non-trivial modulo operation.

[How]
Replace arg1 with arg2 in the subtraction term to correctly
implement fmod(arg1, arg2).

Cc: Mario Limonciello <mario.limonciello@amd.com>
Cc: Alex Deucher <alexander.deucher@amd.com>
Cc: stable@vger.kernel.org
Reviewed-by: Dillon Varone <dillon.varone@amd.com>
Signed-off-by: Wenjing Liu <wenjing.liu@amd.com>
Signed-off-by: Aurabindo Pillai <aurabindo.pillai@amd.com>
Tested-by: Dan Wheeler <daniel.wheeler@amd.com>
Signed-off-by: Alex Deucher <alexander.deucher@amd.com>

authored by

Wenjing Liu and committed by
Alex Deucher 2b104fc3 d3a549f4

+1 -1
+1 -1
drivers/gpu/drm/amd/display/dc/dml2_0/dml21/src/dml2_standalone_libraries/lib_float_math.c
··· 23 23 return arg2; 24 24 if (isNaN(arg2)) 25 25 return arg1; 26 - return arg1 - arg1 * ((int)(arg1 / arg2)); 26 + return arg1 - arg2 * ((int)(arg1 / arg2)); 27 27 } 28 28 29 29 double math_min2(const double arg1, const double arg2)